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Cambridge 9709Functions

A Level Maths Functions: Cambridge 9709 Pure 1 Complete Guide

A level maths functions is the first major algebra topic in 9709 Pure 1, and it tests skills you'll use across the entire paper. For Cambridge 9709 Pure 1, Topic 1.2 covers domain, range, one-one functions, inverse functions, composition of functions, and graph transformations. Functions questions appear on every Paper 1 as one of the longer, multi-part questions, worth around 8-12 marks. Understanding functions also feeds directly into differentiation and integration, making it foundational for the entire course.

This guide is part of our Complete Cambridge 9709 Pure 1 Revision Guide — your comprehensive resource for exam preparation.

What A Level Maths Functions Means in 9709 Pure 1

A function is a rule that takes an input and produces exactly one output. You've been using functions since GCSE — y = 2x + 3 is a function — but A-Level formalises the language. That language matters, because 9709 exam questions test whether you understand the terminology, not just whether you can do the algebra.

The modulus function |f(x)| is Pure 3 only. Don't waste revision time on it for Paper 1. Everything in this guide is strictly what the 2026 − 2027 syllabus requires for Pure Mathematics 1.

Domain and Range in A Level Maths Functions

Domain = what goes IN (the x-values the function accepts). Range = what comes OUT (the y-values the function actually produces).

For a linear function like f(x) = 2x + 1, the domain is all real numbers and the range is all real numbers. Quadratic functions are where it gets interesting. Take f(x) = x² − 4x + 7. Complete the square: f(x) = (x − 2)² + 3. The minimum value is 3 (when x = 2), so the range is f(x) ≥ 3.

Two notations appear in 9709: f(x) = 2x + 1 (most common) and f : x ↦ 2x + 1 (mapping notation). Both mean the same thing and the exam uses both interchangeably.

Composite Functions in A Level Maths — fg(x) Explained

A composite function is a 'function of a function.' You feed the output of one function into another: fg(x) = f(g(x)).

The order rule that trips everyone up: fg(x) means 'do g first, then f.' Read right to left. Think of it like getting dressed — 'socks then shoes' means you put socks on first, shoes second.

Example: f(x) = x², g(x) = x + 3. Then fg(x) = f(g(x)) = f(x + 3) = (x + 3)². But gf(x) = g(f(x)) = g(x²) = x² + 3. Completely different results.

Inverse Functions in A Level Maths — Finding f⁻¹(x)

An inverse function 'undoes' what the original function does: ff⁻¹(x) = f⁻¹f(x) = x. An inverse only exists for one-one functions.

To find the inverse: (1) Write y = f(x). (2) Swap x and y. (3) Rearrange to make y the subject. (4) Replace y with f⁻¹(x). (5) State the domain (= range of original f).

The graph of f⁻¹(x) is the reflection of f(x) in the line y = x. If a question asks you to solve f(x) = f⁻¹(x), do not assume you can simply solve f(x) = x — this only finds solutions that happen to lie on y = x, and there may be others. The safest method is always to solve f(x) = f⁻¹(x) directly and algebraically.

Graph showing f(x)=x² and its inverse f⁻¹(x)=√x as reflections in the line y=x, with corresponding points (1,1) and (2,4) labelled on both curves
f(x) and f⁻¹(x) are reflections in the line y = x

How Functions Connects to Other Topics

Functions isn't isolated — it's the language that every other Pure 1 topic uses.

Differentiation: When you differentiate f(x) = x³ − 2x, you're finding f'(x). The chain rule for differentiating composite functions like (2x + 1)⁵ directly uses the concept of composition. If you understand fg(x), the chain rule makes more sense. See our 9709 differentiation guide for more.

Integration: Integration is the reverse of differentiation, which is the same idea as an inverse function. The definite integral also requires understanding domain restrictions — you can only integrate over an interval where the function is defined. See our 9709 integration guide for the full method.

Quadratics: Completing the square to find the range of a quadratic function is pure functions territory. If you are not confident completing the square, that's worth revisiting in our 9709 quadratics guide — it appears in almost every functions question involving range or inverse.

Trigonometry: Graph transformations apply directly to trig graphs. When you meet y = 3sin(2x) + 1, you're applying a vertical stretch (scale factor 3), a stretch of scale factor ½ parallel to the x-axis (this halves the period — the graph gets narrower), and a vertical translation of +1 to y = sin(x). Apply the translation last. See our 9709 trigonometry guide for more on trig graph transformations.

What to Do Next

A level maths functions is the language of the entire course. Master the terminology (domain, range, one-one, many-one), the methods (finding inverses, forming composites, applying transformations), and the exam techniques (stating domains, using correct vocabulary, showing working), and you've built the foundation for everything else in Pure 1.

The most common marks lost in functions come from three places: getting composite function order wrong (fg vs gf), forgetting to state the domain of f⁻¹, and using incorrect transformation vocabulary. All three are avoidable with careful practice.

ExamPilot's adaptive practice identifies exactly which functions sub-skills you need to work on. Instead of grinding through random questions, you practice the ones that target your specific gaps — with Ask Sparky available to guide you when you're stuck.

Looking for past paper practice? See our 9709 Past Papers by Topic collection.

Functions feeds directly into the next major topic. Read our 9709 Differentiation Guide to see how function notation and the chain rule connect.

Key Formulas

Composite Functions

fg(x)=f(g(x))fg(x) = f(g(x))
Apply g first, then f — read right to left

The function closest to x acts first. fg(x) means: feed x into g, then feed the result into f. Think of it like getting dressed — 'socks then shoes' means socks go on first.

Domain of fg: range of g domain of f\text{Domain of } fg: \text{ range of } g \subseteq \text{ domain of } f
The composite fg(x) only exists when the range of g fits within the domain of f

Inverse Functions

ff1(x)=f1f(x)=xff^{-1}(x) = f^{-1}f(x) = x
An inverse undoes the original function

To find the inverse: write y = f(x), swap x and y, rearrange for y, then replace y with f⁻¹(x). Always state the domain of f⁻¹ (it equals the range of the original f).

Domain of f1=Range of f,Range of f1=Domain of f\text{Domain of } f^{-1} = \text{Range of } f, \quad \text{Range of } f^{-1} = \text{Domain of } f
Domain and range swap between a function and its inverse

Graph Transformations

y=f(x)+a (up by a),y=f(x+a) (left by a)y = f(x) + a \text{ (up by } a\text{)}, \quad y = f(x+a) \text{ (left by } a\text{)}
Translations — vertical does what you expect, horizontal is opposite
y=af(x) (vertical stretch, scale factor a),y=f(ax) (stretch parallel to x-axis, scale factor 1a)y = af(x) \text{ (vertical stretch, scale factor } a\text{)}, \quad y = f(ax) \text{ (stretch parallel to } x\text{-axis, scale factor } \tfrac{1}{a}\text{)}
Stretches — horizontal scale factor is the reciprocal
y=f(x) (reflect in x-axis),y=f(x) (reflect in y-axis)y = -f(x) \text{ (reflect in } x\text{-axis)}, \quad y = f(-x) \text{ (reflect in } y\text{-axis)}
Reflections

Worked Examples

Finding the range of a quadratic function

Easy[2 marks]
The function f is defined by f(x) = x² − 2x + 5 for x ≥ 1. Find the range of f.

Composite functions — fg(x)

Easy[4 marks]
Functions f and g are defined by f(x) = 3x − 1 and g(x) = x² + 2. Find fg(x) and evaluate fg(2).

Finding the inverse of a linear function

Easy[2 marks]
The function f is defined by f(x) = 2x + 5 for x ∈ ℝ. Find f⁻¹(x).

Finding the inverse with restricted domain

Medium[5 marks]
The function f is defined by f(x) = x² − 6x + 11 for x ≥ 3. Find f⁻¹(x) and state its domain.

Self-inverse function proof

Medium[3 marks]
The function f is defined by f(x) = (3x + 1)/(x − 3) for x ≠ 3. Show that f is self-inverse.

Describing graph transformations

Medium[4 marks]
Describe the sequence of transformations from y = f(x) to y = 3f(x − 2) + 1.

Domain of a composite function

Medium[3 marks]
Functions f and g are defined by f(x) = √x for x ≥ 0 and g(x) = 2x − 5 for x ∈ ℝ. Find the domain of fg(x).

Multi-part functions question

Hard[8 marks]
The function f is defined by f(x) = (3x + 1)/(x − 3) for x ≠ 3. (a) Show f is self-inverse. (b) State the domain of f⁻¹. (c) Solve f(x) = x. (d) Hence find where y = f(x) meets the line y = x.

Common Mistakes

Getting fg(x) and gf(x) the wrong way round — applying f first instead of g

fg(x) means do g first, then f. Read right to left: fg(x) = f(g(x)). The function closest to x acts first. Examiner reports flag this as the most common procedural error in functions questions.

Saying a function has no inverse because of domain issues, not because it's not one-one

A function needs to be one-one (passes horizontal line test) for an inverse to exist. A significant number of candidates incorrectly stated the function was undefined, rather than identifying that it was not one-one. Understand the difference.

Forgetting to state the domain of f⁻¹(x)

The domain of f⁻¹ equals the range of the original f. This is a free mark — always state it. If f has domain x ≥ 2 and range y ≥ 5, then f⁻¹ has domain x ≥ 5.

Graph transformation direction errors — thinking f(x+3) shifts right

Changes inside f() affect x and are OPPOSITE to what you expect: f(x+3) shifts LEFT by 3, f(2x) is a horizontal stretch by factor 1/2. Changes outside f() affect y and do what you expect: f(x)+3 shifts UP by 3.

Not using correct transformation vocabulary — saying 'shift' instead of 'translation'

The 9709 syllabus explicitly requires the terms 'translation', 'reflection', and 'stretch'. Using 'shift', 'flip', or 'squash' loses marks even if the description is otherwise correct.

Exam Tips

The Inside-Outside Rule for Transformations

Changes outside f() affect y and do what you expect: f(x)+3 shifts up by 3, 2f(x) stretches vertically by factor 2. Changes inside f() affect x and are opposite: f(x+3) shifts LEFT by 3, f(2x) is a horizontal stretch by factor 1/2.

Summary of all 6 graph transformations of y=f(x) showing vertical and horizontal translations, stretches, and reflections with the key rule: changes inside f() affect x (opposite), changes outside affect y (as expected)
The 6 graph transformations you need for 9709 Pure 1
Graph Transformations Summary
TransformationEquationDescriptionDirection
Vertical translationy = f(x) + aTranslate up by aAs expected
Horizontal translationy = f(x + a)Translate LEFT by aOpposite
Vertical stretchy = af(x)Stretch vertically, factor aAs expected
Horizontal stretchy = f(ax)Stretch horizontally, factor 1/aOpposite
Reflection in x-axisy = -f(x)Flip upside down
Reflection in y-axisy = f(-x)Flip left-to-right

Read Right to Left for Composites

fg(x) means do g first, then f. The function closest to x acts first. Write it as f(g(x)) every time until the order becomes automatic. Cambridge examiners flag this as the most common procedural error in functions questions.

Diagram showing composite function order for fg(x): input x goes into g first, output of g goes into f second, producing f(g(x)). Read right to left.
fg(x) = f(g(x)): do g first, then f — read right to left

Why f(x+3) Moves LEFT

f(x+3) asks 'what does f see 3 units ahead?' At x = 2, f(x+3) evaluates f(5). The output that used to happen at x = 5 now happens at x = 2. The whole curve arrives 3 units sooner, so it shifts left.

Graph showing f(x)=x² and f(x+3) with annotation: the output that happened at x=5 now happens at x=2, shifting the whole curve 3 units left
Why f(x+3) moves LEFT: the input reaches the target value 3 units sooner

The Horizontal Line Test

An inverse only exists for one-one functions. Use the horizontal line test: if any horizontal line crosses the graph more than once, the function is many-one and has no inverse unless you restrict the domain.

Side-by-side comparison: one-one function f(x)=2x+1 (horizontal line crosses once, passes test) and many-one function f(x)=x² (horizontal line crosses twice, fails test)
The horizontal line test: one-one functions have inverses, many-one functions don't

3-Stage Revision Strategy

Stage 1 (2-3 sessions): Master the concepts — domain/range, notation, the inverse method, and the composite method. Don't move on until you can explain each concept without notes.

Stage 2 (3-4 sessions): Apply to exam contexts — do past paper functions questions by sub-topic. Start with inverse function questions, then composites, then transformations. Check your answers against mark schemes.

Stage 3 (ongoing): Timed mixed practice — mix all sub-topics together under timed conditions. Functions questions in the actual exam combine concepts, so practising mixed questions builds the fluency that scores full marks.

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