9709 Pure Mathematics 1 Oct/Nov 2022 Paper 11
9709 Pure Mathematics 1 Oct/Nov 2022 Paper 11: all 24 questions and parts with their marks, taken from the published mark scheme rather than estimated.
Every question in 9709 Pure Mathematics 1 Oct/Nov 2022 Paper 11
24 questions and parts, 75 marks in total. Marks come from the published mark scheme.
Question 1
3 marks · 3/75Question 2 (a)
2 marks · 5/75Finding the tangent to a curve from its derivative and a point on the curve.
Examiner report: A recurring issue was treating the derivative as something to integrate, or using its reciprocal and thereby finding a normal rather than a tangent.
Question 2 (b)
4 marks · 9/75Recovering a curve equation by integrating its gradient and using a point condition.
Examiner report: Errors commonly arose from incorrect powers and from omitting the factor required by the inner linear expression. Some candidates also interchanged the coordinates when applying the point condition.
Question 3
5 marks · 14/75Using the stationary-point condition to determine a parameter and then find a coordinate.
Examiner report: Although differentiation was usually attempted, mistakes in fractional powers and coefficients were frequent. Some candidates substituted their parameter into the derivative instead of returning to the original equation.
Question 4
6 marks · 20/75Using selected binomial coefficients to determine a parameter from the coefficient of a specified power.
Examiner report: Expanding every term was unnecessary and sometimes led to errors. Common slips included failing to square the factor involving p and omitting one sign when taking square roots.
Question 5 (a)
4 marks · 24/75Finding the perimeter of a circular segment using sector geometry and a chord length.
Examiner report: A frequent misconception was to treat the two radii and chord as an equilateral triangle. Candidates also sometimes confused radian measures with degree measures when finding the chord.
Question 5 (b)
2 marks · 26/75Finding the area of a minor circular segment.
Examiner report: The required decomposition into sector area minus triangle area was sometimes missed. Incorrect angle units, or using the full central angle in a half-triangle calculation, caused further errors.
Question 6 (a)
3 marks · 29/75Algebraic manipulation of a trigonometric equation into a quadratic in sine.
Examiner report: Incomplete working was a problem in this show-that part. Candidates often struggled with the common denominator or applied the squared-sine and squared-cosine identity incorrectly.
Question 6 (b)
3 marks · 32/75Solving a trigonometric equation by first solving a quadratic in sin θ and then locating all angles in an interval.
Examiner report: Some solutions contained only one of the valid angles because the later quadrants were overlooked. Rounding to the specified degree accuracy was also inconsistent.
Question 7 (a)
3 marks · 35/75Using the terms of a geometric progression to verify when a quantity first falls below a threshold.
Examiner report: Several candidates treated the data as an arithmetic rather than geometric progression, or inverted the common ratio. A conclusion identifying the first qualifying impact was required, not just two numerical comparisons.
Question 7 (b)
2 marks · 37/75Finding the sum of a fixed number of terms of a geometric progression and applying a rounding instruction.
Examiner report: The series formula was often selected correctly, but some candidates failed to apply the specified rounding. Directly adding rounded individual terms also led to avoidable inaccuracies.
Question 7 (c)
2 marks · 39/75Finding the limiting total of a convergent geometric progression.
Examiner report: This part was generally handled more successfully with the standard infinite-series formula. Summing terms individually was less reliable and often introduced rounding or arithmetic errors.
Question 8 (a)
3 marks · 42/75Differentiating a reciprocal linear function and using the derivative to determine monotonicity.
Examiner report: Some candidates confused derivative notation with inverse-function notation. Other errors involved the chain-rule multiplier, the power in the denominator, or failing to interpret the sign of the derivative.
Question 8 (b)
4 marks · 46/75Finding the inverse of a rational function and expressing it in a prescribed form.
Examiner report: The general inverse-function approach was understood by many, although sign and algebraic rearrangement errors remained common.
Question 8 (c)
1 mark · 47/75Question 9 (a)
1 mark · 48/75Question 9 (b)
2 marks · 50/75Question 9 (c)
1 mark · 51/75Relating two quadratic functions through a shifted input and a vertical scale factor.
Examiner report: Many candidates found the mapping notation difficult to interpret and did not successfully connect the two completed-square representations.
Question 9 (d)
4 marks · 55/75Describing the separate graph transformations represented by a function relation.
Examiner report: Some responses identified one transformation but omitted or misdescribed the other. Precise directional language and a clear scale description were needed for full credit.
Question 10 (a)
5 marks · 60/75Finding the area enclosed between two intersecting curves by integration.
Examiner report: Typical mistakes included mishandling fractional exponents or coefficients during integration and reversing the limits without compensating for the sign.
Question 10 (b)
5 marks · 65/75Finding the acute angle between two tangents from their gradients.
Examiner report: This was a demanding problem-solving part. Successful approaches began with both gradients and then used inverse tangent, tangent equations with geometry, or a right-triangle construction.
Question 11 (a)
4 marks · 69/75Finding tangent gradients to a circle by imposing a repeated-intersection condition.
Examiner report: Arithmetic and algebraic slips in forming the quadratic were common. The tangency condition had to be expressed through a zero discriminant rather than merely finding ordinary intersections.
Question 11 (b)
3 marks · 72/75Finding the coordinates of points of contact between tangents and a circle.
Examiner report: Candidates used either substitution into the quadratic or the perpendicular tangent-normal method. Some found one point but did not complete the symmetric pair or paired coordinates incorrectly.
Question 11 (c)
3 marks · 75/75Using circle geometry and trigonometry to determine an angle subtended by two contact points.
Examiner report: This was difficult for many candidates. The most effective solutions used either the cosine rule, a central-angle argument, or complementary angles formed with radii and vertical lines.
Grade thresholds for this paper
| Session | Paper | A | B | C | D | E |
|---|---|---|---|---|---|---|
| 9709 Pure Mathematics 1 Oct/Nov 2022 Paper 11 | 11 | 57 | 46 | 37 | 28 | 19 |